Given the equation of a proton v(vector)=4.0i-2.0j+3.0k for 4 seconds, what is the proton's average acceleration in unit-vector notation? Any help here would be great guys. I know how to find the magnitude of the acceleration vector (which should be 1.346 m/s^2) if that helps. Thank you all in advance!|||Acceleration (x-axis) = 4/4 = 1 m/ s^2
Acceleration (y-axis) = -2/4 = -0.5m/ s^2
Acceleration (z-axis) = 3/4 = 0.75 m/ s^2
thus,
a = 1.0i - 0.5j + 0.75k
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