I need to check if (my book writes these as column vectors)
(2, 6, 6) is in the span of (-1, 2, 3) and (3, 4, 2).
So I know what it's asking. It's asking if some linear combination of the last two vectors produces the 1st vector.|||Check the determinant of matrix
2 -1 3
6 2 4
6 3 2
If it is =0 it means that (2,6,6) is a linear combination of the last two vectors.
If not all three vectors are independent.|||Let r, s be some real numbers. For [2, 6, 6] to be a linear combination of the other two vectors: there must be some scalar multiple of the other two that gives us the [2, 6, 6] vector.
[2, 6, 6] = r [-1, 2, 3] + s [3, 4, 2]
Then:
2 = -r + 3s
6 = 2r + 4s
6 = 3r + 2s
Now to solve for r and s. If we can find some values for them that works, then it is in the span of the two vectors.
Add 2 of the first equation to the 2nd equation:
6 + 4 = (2r + 4s) + (-2s + 6s)
10 = 10s
s = 1
Plug s = 1 into one of the original equations.
6 = 3r + 2s
6 = 3r + 2(1)
6 - 2 = 3r
4 = 3r
r = 4/3
Plug these values into the first equation:
2 = -r + 3s
2 = (-4/3) + 3
-1 = -4/3
That is obviously not true. Thus, not in the span.
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