Is it just like vector addition, using position vectors to find the line between the two points?|||If you have learned about directional derivatives, take the direction of the tangent * the directional derivitve of that point to find the vetcor.|||ax + by = c =%26gt; y = -ax/b + c/d
M1(x1; y1 = -ax1/b + c/d ) ; M2(x2; y2 = -ax2/b + c/d)
vector M1M2 = (x2-x1, y2-y1)
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