for what value of a are the vectors 60i + 3j,40i - 8j,ai - 52j collinear??|||the position vectors of the points are given i think.
let the pts be A,B,C
then vector AB = (40i - 8j)-(60i + 3j) = -20i -11j
and vector BC = (ai - 52j)-(40i - 8j) = (a -40)i - 44j
as they are collinear,
(a-40)i - 44j = m(-20i -11j)
then,
a-40 = -20m
and -44 = -11m
or m =4
so a-40 = -80
or,a = -40
ans : a = -40
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment