I need a vector, any vector, that is perpendicular to the line that passes through [0,0,0] and [9,2,1]??
How would I find one?
Any help is appreciated!|||tHE LINE HAS A DIRECTION D= (9,2,1) -(0,0,0) = (9,2,1)
a perpendicular vector ( see Gram -Smith process) may be obtained from any vector .-
Suppose the vector V .- The projection over D is Vd = IVI cosT T angle between both .-
cos T = D dot V / I DI I VI , ie Vd= IVI cos T = D dot V / IDI , BUT in the D direction , ie on the unit D direction %26lt;D%26gt; = D / IDI
Vd= IVI cos T %26lt;D%26gt; = ( D dot V / IDI^2 ) D
Then Vd + Vn = V , Vn is the normal component of V .- we are looking for just Vn .-
Vn= V- Vd
Vn= V -( D dot V / IDI^2 ) D
Take any vector , V= i D dot V= 9 , IDI^2 = 81+4+1= 86
Vn= i - (9/86) (9,2,1)
Vn= ( 5/86 , -18/86 ,-9/86)
Check , Vn dot D = 45/86 -36/86- 9/86 = 0 ok /
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