A force vector has a magnitude of 591 newtons and points at an angle 40o of below the positive x axis. What ar?

A force vector has a magnitude of 591 newtons and points at an angle 40 degrees below the positive x axis. What are (a) the x scalar component and (b) the y scalar component of the vector?|||Scalar values = magnitudes (without direction)





Fx = 591.cos40 = 452.70 N





Fy = 591.sin40 = 379.90 N