What is the direction of the displacement vector?

You are walking 44 m North. You then turn 60 degrees to the right and continue to walk for another 45 m. What direction is the displacement vector?|||Let X axis due East and Y axis due North.


Then the components of the displacement vector V are:


Vx = 45*sin60° = 38.97 m


Vy = 44 + 45*cos60° = 66.5 m


and


tanα = Vx/Vy = 0.586


α = 30° North to East.|||start off by drawing a diagram, show a line going north on a piece of paper and label it 44m, then draw another line 60 degrees to the right of north going 45m, then use vector addition and law of cosines and sines to find the magnitude and then find the direction