How do you determine if a vector is parallel, perpendicular, or neither?

Is there like a one step process where you can determine it?





Take this for example:


u=%26lt;8,5%26gt;


v=%26lt;-2,4%26gt;





Is this vector parallel, perpendicular, or neither? What are the process for each? How do u know when its not parallel, perpendicular, or neither?|||Hi,





If it's perpendicular, its dot product or scalar product will equal zero.





For vectors %26lt;x1, y1%26gt; and %26lt;x2, y2%26gt;, the dot product is x1*x2 + y1*y2. For your vectors, it is 8(-2) + 5(4) = -16 + 20 = 4. They are not perpendicular.





If they were parallel there would be a scalar you could multiply times the x and y of one vector to equal the other vector.





-2 times -4 equals 8 for the x values, but 4 times -4 does not equal 5. Therefore they are not parallel either.





By process of elimination, they are neither.





I hope that helps!! :-)|||u have to finde the slope of it if it is paralell it has to be equal ,for perpendicular the multiple of them has to be -1|||If two vectors are perpendicular to each other, then the dot product is zero:





ux*vx + uy*vy = 0





In your example: 8*(-2) + 5*4 = -16 + 20 = 4, so these vectors are not perpendicular to each other.








magnitude of u: um = sqrt( ux^2 + uy^2 )


magnitude of v: vm = sqrt( vx^2 + vy^2 )





If two vectors are parallel, then the dot product is equal to the product of the magnitudes:


ux*vx + uy*vy = um * uv





In your example,


um = sqrt( 64 + 25 ) = sqrt ( 89) = 9.434


uv = sqrt( 4 + 16 ) = sqrt( 20 ) = 4.472


The product = 42.190, but the dot product is 4, therefore these vectors are not parallel.





The angle between the vectors can be found like this:





cos(Th) = dot product / (product of magnitudes)





For this example: cos(Th) = 4 / 42.190 = 0.0948


Th = 1.476 radians = 84.560 degrees.|||Well you can take (8,5) and (2,4) and just put them on graph paper, we just started this unit in school too|||It's been decades since I did geometry, but I think the direction of u is atan(8/5); the direction of v is atan(-2/4). So the angle between them is 84.5 deg. Does my brain still work after all that time?|||For a pair of vectors with non-zero components, simply divide the components in a like manner. If the values are identical, then the vectors are parallel. If the values are equal in absolute value, but opposite in sign, then they're perpendicular. Failing those two tests, you get "neither."





If you end up having to divide by zero (which you won't do), then you have infinite slope, so only if both had a zero in the corresponding components would the vectors be parallel; if they have zeroes in the opposite components, then they're perpendicular. Failing those two tests, you get "neither."

Where can I get a cheap vector image of a peacock?

I am looking for a royalty free vector of a peacock. Preferably something that looks like an etching or woodblock print. I don't mind paying for it, but don't want to spend a fortune.|||Some good royalty free micro stock sites:





http://www.istockphoto.com/index.php





http://www.dreamstime.com/





http://www.123rf.com/|||Also try Shutterstock


http://www.shutterstock.com/cat.mhtml?la鈥?/a>

How do I convert a cartesian vector into spherical coordinates?

Specifically, how do I represent:





r(x,y,z) = xi + yj + zk





As a vector fuction of ro, theta and phi?|||ro^2 = x^2 + y^2 + x^2





ro = sqrt(x^2 + y^2 + x^2)





cos(phi) = z / ro





cos(theta) = x / (ro * sin phi)|||x=p*sin(phi)*cos(theta)


y=p*sin(phi)*sin(theta)


z=p*cos(phi)





So however you want to represent your r(x,y,z), just replace with these conversions.


r(x,y,z)=p*sin(phi)*[i*cos(theta)+j*si鈥?for example.

How do you invert a vector mask in Photoshop?

I created a vector mask, but it's masking out the wrong part.|||a simple way to do it would be to finish the mask in the shape you want, then convert it to a selection and choose the inverse selection.|||here try out what these guys are saying...been a while since Ive messed with vector masks





http://objectmix.com/adobe-photoshop/231鈥?/a>

In general, how would you sketch a vector that was n times a given vector? How would the lengths and headings?

In general, how would you sketch a vector that was n times a given vector? How are the lengths and headings of these two vectors related?|||The lengths would be n times as long as the original and the heading would be exactly the same.|||A scalar multiple of a vector is the same direction and 'scaled' in magnitude by the value.





That is, their 'headings' are the same, but their lengths are relative to the scalar by which they were multiplied.





Doug|||if n is a scalar and not a vector then the length of the vector changes by a factor of n (new length = old length * n) and the direction remains constant.





If n is another vector with magnitude n and a direction then the vectors are multiplied using vector multiplication rules and the resultant will have a different magnitude and direction.

Where I can get my logo converted to vector file with lowest price?

I run a small business and I have some logos to be converted to vector file,but my budget is very low.So


Where I can get my logo converted to vector file with lowest price? How much is it ?|||Email me with the specifics and a picture of your current logo. I understand your budget concerns and I'll work with you on the price.





mattymjb@yahoo.com|||I could convert these logos for you for cheap. I am a freelance graphic designer with over 10 years of experience. I work with many screen printers and other business owners on a daily basis converting their logos to vector format. I could probably do them each for $10. But I would have to see how complex they are first. Email me the logos and I will give you an exact price. I am ready to start on these ASAP.|||This company provide a eye-catching logo conversion service! Their price is very reasonable!


Look at this page to know more information！





http://www.pgconversion.com/price_guide.htm

How to find a unit vector that is normal (perpendicular) to a plane determined by three points?

Find a unit vector that is normal (perpendicular) to the plane determined by the points A(1, - 1, 2)


,B(2,0, - 1) and C(0,2,1).





I have no idea whatsoever about how to solve this one. All help is really appreciated!|||Form two vectors with your points. e.g.





AB = (1, 1, -3) and AC = (-1, 3, -1).





The cross product of these will be normal to the plane. To get a unit normal, just divide the cross product by its magnitude.





v = AB x AC = (8, 4, 4).





||v|| = 鈭?8虏 + 4虏 + 4虏) = 4鈭?6).





n = v/||v|| = (2/鈭?6), 1/鈭?6), 1/鈭?6)).

How do you write a vector equation with the given info?

How do you write a vector equation of the line that passes through (6, 1) with a slope of -2/3?|||If the slope is -2/3, this means it is "rise/run" or Δy / Δx. Therefore, we can split this up into x and y components:





Δy = -2


Δx = 3





And make a vector out of them:





%26lt;Δx,Δy%26gt;


%26lt;3,-2%26gt;.





Now that we have our slope vector, and our initial position vector, %26lt;6,1%26gt;, we can write the equation of a line.





r(t) = r0 + v*t


r(t) = %26lt;6,1%26gt; + %26lt;3,-2%26gt;t


r(t) = %26lt;6,1%26gt; + %26lt;3t, -2t%26gt;


r(t) = %26lt;(3t + 6), (1 - 2t)%26gt;

Is there an open source vector drawing program similar to adobe illustrator?

I am in need of an open source vector drawing program VERY similar to Adobe Illustrator... Any sites and or programs that could help me out?|||get illustrator, its worth it.

How do I solve this vector problem for my phyics homework?

V is a vector 14.3 units in magnitude and points at an angle of 34.8 degrees above the negative x axis





a)find Vx and Vy


b)use Vx and Vy to obtain (again) the magnitude and direction of V.|||a)Vx=Vcos(180-34.8)=14.3cos(145.2)


Vy=Vsin(180-34.8)=14.3sin(145.2)


b) V^2=Vx^2+Vy^2

Is there a way to find a perpendicular vector without using a matrix/cross product?

I need help with finding perpendicular vectors, is there a way of finding a perpendicular vector to two others without using a matrix/ cross product rule?|||Hello



Yes, you can use the scalar product: the scalar product of two perpendicular vectors = 0:



Let your two vectors be (1,2,3) and (4,5,6). And the unknown vector = (x,y,z), then set up



(x,y,z)*(1,2,3) = 0 and

(x,y,z)*(4,5,6) = 0

-------

which is written out:

x + 2y + 3z = 0 and

4x + 5y + 6z = 0



now set x = any number, like x = 1:

and solve for y and z:



(1): 1 + 2y + 3z = 0 --%26gt; *2

(2): 4 + 5y + 6z = 0

-------------------

(3): 2 + 4y + 6z = 0 --%26gt; (2-3):

2 +y = 0

y = -2 plug into (1)

1 - 4 + 3z = 0

z = 1



the vector (1, -2,1) is perpendicular to (1,2,3) and (4,5,6)



Regards|||You don't have to use a matrix. You can calculate the coefficients of the perpendicular vector directly. This formula is from wikipedia:


a 脳 b = (a2b3 鈭?a3b2) i + (a3b1 鈭?a1b3) j + (a1b2 鈭?a2b1) k


a 脳 b = (a2b3 鈭?a3b2, a3b1 鈭?a1b3, a1b2 鈭?a2b1).


where


a= a1i+a2j+a3k


b = b1i+b2j+b3k





Or if a and b lie in one of the coordinate planes, you can calculate the magnitude of the vector from:


|a| |b| sin(theta)


and then manually assign the third unit direction vector.

How do I find a vector that is perpendicular to a plane?

Let P be the plane in space that intersects the x-axis at 1, the y-axis at -4, and the z-axis at -2. Find a vector v that is perpendicular to P.|||The intersection information can be interpreted as the plane passes through the points (1, 0, 0), (0, -4, 0) and (0, 0, -2).





Okay, lets call these points A, B, and C. The vectors AB and AC (initial end at A and terminal end at B or C) both lay in the plane P. These vectors are





AB = (-1, -4, 0) and AC = (-1, 0, -2).





The normal to the plane has to be perpendicular to both of these vectors. This just screams cross product! A vector perpendicular to the plane is





v = AB x AC = (8, -2, -4).





You can take any nonzero scalar multiple of this.

How can I store a number in a vector in matlab?

I have to write a function in matlab.


it will prompt the user for a number, and then store the number in a vector and ask for another number until a negative number is given, then the function will stop and return the vector of positive numbers previously stored.


Thanks so much!|||The command that you want to use in your function will be "INPUT".





You would use it something like this:





a = input("Enter a value: ")





The variable "a" will hold the numeric value and then you can test to see if it is less than zero. If not, then you can assign the value of "a" to the next index in your vector.

What is the equation for percent diffrerences using vector addition and force table experiment.?

I need to know how to calculate the percent difference. I know the general equation, but do not know the variation to use for the vector addition and force table experiment.





I know it needs to be something like %diff (exp-act/act) x 100%





However, with the vector addition experiment, we did not recieve an actual. Is it something that should be obvious?|||I presume you hung some known weights from the table and then experimentally found the weight (and its location) that would balance the known weights. This balancing weight and the angle of its placement are the experimental values.


You can also calculate, algebraically, what the balancing weight should be and where it should be placed. This would be your actual value(s).


OR


You can graphically determine the actual value(s).


Either way these non-experimental methods would be what goes in the "act" part of the error eq.


You could actually have two error eqs. One for the magnitude of the balancing weight and one for the angle of its location.





Note: if you are trying to balance more then one known weight the answer "act" is not obvious and requires calculation.


If you are only trying to balance one known weight then the answer "act" is obvious; equal and opposite.

How to draw a velocity vector for these three situations?

A marble is positioned at the top of a ramp and the ramp is placed on a table top. Draw a velocity vector for when


1) the ball just rolls off the table top


2) in mid flight


3) just before it hits the ground





please help me, my teacher isn't a good one and i have no idea what to do.|||1. Just before the ball rolls off the table top it is going horizontally.


2. In mid-flight it is going both horizontally and vertically downward.


3. Just before hitting the ground it is still going horizontal and vertically downward but this time the vertical component is bigger than before.|||It is pretty much how jcm said (unless we are building a wrong mental image, ofc).





I think this page is a good one to understand how the movement works (and therefore how the velocity vector behaves): http://www.physicsclassroom.com/class/1d鈥?/a>








Basically all you need to do is look at a given instant (the ball leaving the table, for example) and imagine: If there was no gravity, no friction or any other force, in what direction would the marble continue its movement after this instant? It will be a straight line and the vector follows it (you will just not have a precise size, but the overall direction you get).

How do you find a vector equation when given a scalar equation?

For example: 3x-5z+15=0, how would i find the vector equation of this?|||Did you mean to write "z" instead of "y"? If so we are dealing in three dimensions and the equation is that of a plane, not a line. I will assume what you wrote is correct.





The normal vector n, of the plane can be taken from the coefficients of the variables.





n = %26lt;3, 0, -5%26gt;





Now we need to find a point in the plane. Let z = 0 and solve for x. y can be anything so let y = 0 also.





3x + 15 = 0


3x = -15


x = -5





So we have the point P(-5, 0, 0).





Define an arbitrary point in the plane R(x,y,z). Then the vector PR lies in the plane. The normal vector is orthogonal to any vector that lies in the plane. And the dot product of orthogonal vectors is zero.





n 鈥?PR = 0


n 鈥?%26lt;R - P%26gt; = 0


%26lt;3, 0, -5%26gt; 鈥?%26lt;x + 5, y - 0, z - 0%26gt; = 0

How do I insert the vector sign above a letter in microsoft office 2010?

I'm trying to write out a formula for physics, but I don't know how to insert the vector sign above letters.|||Use the character map.

How can I convert a jpg of a character into cut ready vector format?

Hi all,


I have a 4" high jpg of some characters that I need to convert into cut-ready vector format.


Can anybody tell me how I can achieve this?


Thanks in advance,


Matt|||It needs to be traced in a vector graphics program. Adobe Illustrator can do it easily. If you haven't go that then the free Inkscape - http://inkscape.org/ - can. See http://inkscape.org/doc/tracing/tutorial鈥?/a>

How to solve a Gradient Vector question with a square root?

What is the gradient vector of the function





f(x,y,z)= 9 SQRT(x^2+y^2+z^2)





Ive tried to solve it several different ways and i still can figure it out, i think im not converting the SQRT to exponents correctly.|||grad F = 鈭侳/鈭倄I + 鈭侳/鈭倅J + 鈭侳/鈭倆K





I,J,K are usual unit vecdtors.








鈭侳/鈭倄 = 鈭?鈭倄[9鈭?x虏 + y虏 + z虏)]





= 9[1/2 (x虏 + y虏 + z虏)^-1/2 X(2x)]





鈭侳/鈭倄 = 9x / 鈭?x虏 + y虏 + z虏)





By symmetry





鈭侳/鈭倅 = 9y / 鈭?x虏 + y虏 + z虏)








鈭侳/鈭倆 = 9z / 鈭?x虏 + y虏 + z虏)








gradF = [9x /鈭?x虏+ y虏+z虏)]I + [9y /鈭?x虏+y虏+z虏)]J + [9z /鈭?x虏+y虏+z虏)]K





= [9 / 鈭?x虏+y虏+z虏)] [xI + yJ + zK]





Remember vector %26lt; r %26gt; = xI + yJ + zK





also r虏 = x虏+y虏+z虏





so r = 鈭?x虏+y虏+z虏)





Hence gradF = 9(%26lt; r %26gt; / r)





Note: there is no easy way to represent vectors here so I have





used %26lt; r %26gt; to represent actual vector and r to represent magnitude of vector.

How to find an angle relative to the x-axis given a vector?

If I had the x and y component of a vector, such as 4 and 3 respectively, how would I find the angle relative to the x-axis? Thank you in advance.|||that's 3 - 4 - 5


check these out :


http://www.onlinemathlearning.com/specia鈥?/a>





Interior Angles


Because it is a right triangle one angle is obviously 90掳. The other two are approximately 36.86掳 and 53.13掳.





answer is 36.86

Why does the angular velocity vector point perpendicular to the plane of rotation?

Is this just convention or is there are physical meaning to the way the angular velocity vector points?|||It does NOT have physical meaning in the sense of something physical actually "pointing" in that direction. But it is a very useful mathematical convention. In particular, it allows you to use standard vector math to relate angular velocity, angular momentum, angular accelation and torque. It allows you to adopt a useful definition of angular momentum in terms of the cross-product of two vectors (the linear velocity vector of a particle on the rotating object, crossed with its displacement vector from the axis), and similarly define torque as the cross product of two vectors (force × displacement from axis).





If you adopt all these conventions for the various vectors, you can then write vector relationships for torque, angular momentum, angular acceleration and angular velocity, which are exact analogs of the vector relationships for force, linear momentum, linear acceleration and linear velocity.|||It has physical meaning. Look at how a Gyro-compass works. It takes force to change the direction of the angular velocity and angular momentum vectors. In aircraft, the gyro-compass it adjusted to point to True North (usually) at engine start-up. The aircraft can then turn in any direction and the vectors will keep the gyroscope pointed north





http://en.wikipedia.org/wiki/Gyro_compas…


http://en.wikipedia.org/wiki/Angular_mom…


http://en.wikipedia.org/wiki/Angular_vel…

How do you find a vector perpendicular to two parallel planes?

Plane 1: 3x+4y-2z=6


Plane 2: 3x+4y-2z=10





Write down a vector v with tail in plane 1 and head in plane 2 such that v is perpendicular to both the planes 1 and 2.|||I really wish I had more time to help with this, but I can very briefly get you started. Whichever is perpendicular to the first is perpendicular to the second if they are both parallel.





Now I might be entirely wrong about this, but I think looking into this page might help you:





http://en.wikipedia.org/wiki/Cross_product





I think the answer lies with the cross products of two vectors equaling 0. Remember - I might be entirely wrong about that!





Best of luck anyway :)

Are vector components always considered from the Cartesian origin?

I'm learning vector algebra and I'm being told that you can add or subtract vectors by adding their 'components', but unlike with a line segment only a single x and y value are given for each vector. These two things lead me to believe that when this calculation is performed, the point of the vector that does not have an arrow in it must be the origin of the Cartesian plane. Is this correct?|||Actually there are all kinds of coordinate system. Each of which has different ways to break a vector into its component. The Cartesian you know about. But two other popular coordinate systems are spherical and cylindrical.





The three dimensions in a spherical system are omega, rho, and R. Omega is an angle in the horizontal plane, rho is an angle in the vertical plane, and R is a radius. Typically these three dimensions map as x = R cos(rho)cos(omega), y = R cos(rho)sin(omega), and z = R sin(rho).





The cylindrical coordinates also map onto the x,y,z of Cartesian coordinates. But, as you can see, the spherical and cylindrical coordinate systems do have their counterpart in the Cartesian system. That is to say, even when a vector is given in one of the other coordinate systems, its components can be converted into Cartesian.





Vectors can start and terminate anywhere within a coordinate system. They do not have to begin or end with the origin. But that does mean extra work.





So to ease the amount of calculations needed to come up with the components when the vector is off origin, we simply move it over to the origin mathematically and work the problem that way. Moving the vector to the origin is called translation. Once the result is obtained for the translated vector at the origin, we move the answer back to the initial set of coordinates and that would be the answer of the problem.

How do I find a vector 'a' in 3D space that is perpendicular to two given vectors 'b' and 'c'?

The given vectors are already perpendicular to each other.


The size of vector 'a' is also given.





Either of two solutions are okay.





Thank you.|||The cross product of b and c will be perpendicular to b and c.





So let a = b X c

How do you find both vector and Cartesian equation of a plane?

(a) the plane through the point (1,4,5) and perpendicular to the vector (7,1,4)


(b) the plane through the point (6,5-2) and parallel to the plane x + y - z + 1 = 0|||(a)eqation of a plane equals point time normal vector so egation equals


7(x-1)+1(y-4)+4(z-5)=0


7x-7+y-4+4z-20=0


7x+y+4z-31=0





(b)since its parallel then the planes have same vector or multiple of the vector.


1(x-6)+1(y-5)+1(z+2)=0


x-6+y-5+z+2=0


x+y+z-9=0

How do you convert a vector to one that has the same direction and length but is in standard position?

I would like to know how to do this for any vector, but the specific vector I need to do this to has tail (1/2, 1/2, 1/2) and tip (1, 1, 1).





And by "standard position," I mean a vector with its tail, or starting point, at (0, 0, 0).





Thanks for your help!|||Just subtract the components of the tail of the vector from the components of the tip of the vector. The final standard vector for your specific problem is (1/2, 1/2, 1/2).

How does one know when a bacteria has taken in a cloning vector like a plasmid or phage?

I know how this occurs already, what with the restriction fragments, ligase, sticky ends and everything, but how do we know that the bacteria, say E. coli, have accepted the vector with the human gene inside?|||Usually, you also put a resistance gene or a gene along with your gene of interest that will only function if it had been taken up properly. So for instance, giving the bacteria an ampicillin resistance gene, and growing the bacteria on ampicillin containing medium, the ones that live will be the ones that accepted the vector succesfully.

How do you solve for the x component given only the length of the resultant vector?

Calculate the x component of vector B supposing now that the vector is 25.4 meters long.|||With just the length, you cannot calculate the components. You need the angle.





.|||If the vector is the result of a cross product calculation, it will be orthogonal to the two initial vectors. If it's a sum, its individual components are independently the sums of the initial vectors' components.

A force vector has a magnitude of 591 newtons and points at an angle 40o of below the positive x axis. What ar?

A force vector has a magnitude of 591 newtons and points at an angle 40 degrees below the positive x axis. What are (a) the x scalar component and (b) the y scalar component of the vector?|||Scalar values = magnitudes (without direction)





Fx = 591.cos40 = 452.70 N





Fy = 591.sin40 = 379.90 N

Find the resultant displacement vector as a distance and the bearing of this vector?

A ship sails 50 miles on a bearing of 20 degrees. It then goes 30 miles further on a bearing of 80 degrees. Find the resultant displacement vector as a distance and the bearing of this vector.





If you could show steps I would really appreciate it!|||Alright, what you do is figure out the y and x of each of the vectors first.





First vector:





y=sin(20)50


x=cos(20)50





Second vector





y=sin(80)30


x=cos(80)30





now you need the resultant. Add up the y's and x's





y (of resultant)= sin(80)30+sin(20)50





x(resultant) = cos(80)30+cos(20)50





then use pathagorean theorem.





sqrt( y(of resultant)^2 + x(resulant)^2)= final vector.





To find it's angle:





tan^-1(y/x)





and there you go!

How do you find a unit vector b perpendicular to another unit normal vector?

How do you find a unit vector b perpendicular to another unit normal vector, which is (4/5)i + (2/5)j - (3/5) k





your help would be much appreciated!





Thank you!|||Call our original unit vector u. Call our resulting perpendicular unit vector b.





Set v equal to a cross product of u and another arbitrary unit vector:


b = u ×%26lt;1, 0, 0%26gt;





Remember the cross product will always return a vector perpendicular to both original vectors.





u ×%26lt;1, 0, 0%26gt; =


| î ... ĵ ... ĸ ..|


| ux . uy . uz|


| 1 ... 0 ... 0 |





=


%26lt;0, uz, -uy%26gt;





=


%26lt;0, -3/5, -2/5%26gt;





And then be sure to normalize its magnitude:


%26lt;0, -3/5, -2/5%26gt;/sqrt((3/5)^2 + (2/5)^2) = %26lt;0, 3/5, -2/5%26gt;*5/sqrt(13)





Result:


b = %26lt;0, -3/sqrt(13), -2/sqrt(13)%26gt;

Can two vectors of unequal magnitude add up to give the zero vector?

Can two vectors of unequal magnitude add up to give the zero vector?


Can three unequal vectors? Under what conditions?|||1 no


2 yes when the sup of 2 are equal and opposite to the third|||not 2 vectors but three vectors can|||(1) no


(2) yes


For example, go 4 miles east, 3 miles north, and 5 miles back to starting point.





EDIT


Don't start that example at the North Pole.|||come to think of it, two vectors of unequal magnitude can never add up to give zero vector.





but yes, 2 or more it is able to, under condition that their component x,y,z (assuming 3 dimensions, well you can have 1 dimension or infinite dimensions, it works all the same) add up to zero. which is a commonplace in studies of statics.

Vector...................?

we've got these points P=(-6,4) and R=(4,-8)


PR/PZ=4





argument for that PR is 4 times longer than PZ..|||I am not at all sure what you mean to ask.





Since you give no coordinates for Z, I guess you want to find them.





Use the distance formula to find the distance PR. Divide that distance by 4.


Point Z could be any point on a circle centered on P with the radius equal to PR/4.

Vector............?

An airplane flies from San Francisco to Washington Dc at a speed of 8000km/hr. Assume Washington is due east of San Francisco at a distance of 6000km. Use a Cartesian system of coordinates centered at San francisco with Washington in the positive x- direction. At cruising altitude, there is a cross wind blowing from north to south of 100km/hr.





A)What must be the direction of flight for the plane to actually arrive in Washington?





B)what is the speed in the San Francisco to Washington direction?





C) How long does it take to cover this distance?





D) What is the time difference compared to no crosswind?|||First of all...8000km/hr is a very fast airplane...are you sure that is correct?


If it is...then..for every 8000 km it travels in the x direction, it is pushed by the crosswind 100 km.


Therefore, for every 80 km in the x direction, it is 1 km in the y.


Dividing that into 6000 km, the plane is pushed 75 km south during the entire trip.


The plane therefore needs to aim for 75 km north of DC to reach it.


At this point, it is useful to point out that the new distance [sqrt(6000^2+75^2)] is just over 6000, so the negligable extra amount the plane must travel will not affect the answer by more than maybe a couple tenths.


Solving the triangle, we find that the plane must aim an extra 0.7161599454704084 degrees in the north direction so that the wind will blow it perfectly to DC.


For part B, if it is traveling 8000 km/hr in the barely north and mostly east direction, then, solving the vector triangle, it is traveling 7999.375073232652 km/hr in the east directoin


For the plane to cover the 6000.4ish km/hr distance at 8000 km/hr pace, it will take a very small fraction of a second over 45 seconds.


Therefore, for part D, the difference is a very small fraction of a second...If you need the actual answer for that...you should find someone with more time on their hands to figure it all out perfectly :)


Hope this helps. And i hope its correct

Vector?????

for what value of a are the vectors 60i + 3j,40i - 8j,ai - 52j collinear??|||the position vectors of the points are given i think.


let the pts be A,B,C


then vector AB = (40i - 8j)-(60i + 3j) = -20i -11j


and vector BC = (ai - 52j)-(40i - 8j) = (a -40)i - 44j





as they are collinear,


(a-40)i - 44j = m(-20i -11j)


then,


a-40 = -20m


and -44 = -11m


or m =4


so a-40 = -80


or,a = -40





ans : a = -40

What is the difference between Gradient vector and Normal vector? How are they same?

Which is used for the vector fields and which is used for level surfaces? I am confused between the two since both have different formal.


normal vector is found by doing cross product of 2 tangents orthogonal on the surface. The gradient vector is found using the del operator.|||A Gradient Vector is at right angle to the Field Potential Lines. Streamlines follow the Gradient.





A Normal Vector ias at right angle to a surface (usually the Control Surface)

Where and how can I find cheap vector artists?

I am starting my own business and I have ideas of images I would like to put on my clothes. I've been working with Royalty free vectors, but I'd like to have someone draw and create vector files of my own ideas. Does anyone know how much this would cost and where I could find such artists?|||check out deviantart.com


find a couple artists you like email them and try and make some contacts


most are young up and coming artists





Also, post an add on Craigslist, you will get responses.





You can also try posting fliers at a local art school.|||i freelance. i charge $50 an hour for illustration work.





check out my website: http://www.jenbauman.com





my contact information is on there if you're interested.|||http://www.illustrationsof.com


http://www.clipartof.com (many of the images are available in vector for an additional fee, just contact customer service)

How is the vector conversion service works?

I have lots of designs to be converted to vector file. And i was wondering whether


i can get vector sample file before i pay and how is the vector conversion service works?|||If you have a lot of designs to be converted, I would suggest learning Adobe Illustrator, and converting them yourself, it would save you a ton of money over paying someone to do it.





And you usually can't see a sample of the vector conversion, because it takes a while to do it, so nobody is going to waste their time to convert it just to see if you'll like it. However most services have portfolios, so you can see their prior work.

How to display a vector with out the disp function?

I tried fprintf but i'm not sure how cause the vector will be differrent everytime.|||omg i learning that stuff at school right now and i have no idea what it is

How to find the vector with a given magnitude and same direction?

||v||=5


u=%26lt;3,3%26gt;





how do I find the vector?


I've been stumped since earlier today.


Anyone help me out, please?|||Treat it as a geometry problem. Any vector passing through (3, 3) will have a slope of 1. So, you need a line of slope 1 such that it's length is 5. Let the vector be (x, y). You know that x = y, so we can write the vector as (x, x). From the Pythagorean Theorem,





5 = sqrt(x^2 + x^2) = sqrt(2x^2)





2x^2 = 25





x^2 = 12.5





x ~ 3.54





So, %26lt;3.54, 3.54%26gt;

How to apply two gradients to one vector in Illustrator CS5?

So, I want to make an iPod and apply a vertical gradient so that the top and bottom edges appear lighter, AND a horizontal gradient so that the sides appear lighter (to give a 3D effect) on the same vector? How do I apply two gradients on the same vector? Can I do this?|||Each gradient will have to have it's own vector shape. You can layer these shapes to have a very nice realistic 3D appearance.

How do you group results of computation into one column vector in Matlab?

There are hundreds of possible values for a variable which I obtained through a program that I wrote. I would like to group all these results in to a Nx1 column vector. How does one accomplish this? Many thanks! (N stands for the number of total results.)|||ok ...


you need to put one loop which starts from 1 to N ...


in that loop you need to put your formula ...


let A = f(B) ...


but this will reset A every time ...


so,


now you put


A(i) = f(B(i));


(i is the counter of loop)


this will create a row matrix ....


and for column matrix ,


A(i,1) = f(B(i,1));


here A and B both are column matrix ....


hope it helped !! ........................................鈥? :)

Why to use the normal vector for constructing the plane equation in 3-D Calculus?

Why do people use normal vector for the plane equation in 3-D?


Because in 2-D, we need point and slope, slope is kind of like the vector or the direction of the line, but in 3-D, why do people use normal but not parallel vector? Isn't that only give you the plane equation for the normal vector (which is like the slope) direction instead of the the plane equation that passes through the given points?|||In two dimensions, we can take the normal vector:





%26lt; a , b %26gt;





and turn it into the slope:





- b / a





However, if you have a normal vector in 3D:





%26lt; a , b , c %26gt;





You can't turn it into a fraction - there are three things!


You can't have a "parallel" vector to a plane, since a plane goes many directions. It's also important to remember that the normal vector is more like the slope, whereas the tangent plane is like the tangent line.





Alot of 2D calculus, in high level math, is done with vector methods instead, even though they aren't as necessary.

How do you determine magnitude and direction of a force that completely cancels a resultant force vector?

In the previous question, I determined the resultant force vector has a magnitude of 55.9 N and the direction is 75.4 degrees. Now, I need to find the force of the vector that would completely cancel out that vector. Would it have the same magnitude but just a different direction?|||same magnitude; opposite direction

How can I past vector graphics from Illustrator into Word?

I need scaleable graphics in a document I'm designing, as rastor graphics turn to crap when you PDF them. Can illustrator create a vector file format that can enable the graphics produced to be copied into word files? Thanks in advance...|||Here is a thread on the subject:





http://www.macosxhints.com/article.php?s鈥?/a>





If your raster graphics don't look good in PDF, you should check out the DPI setting when exporting to PDF. Perhaps it is too low so the images are being down-sampled.|||This will help.


http://www.graphic-design-employment.com鈥?/a>|||You can place an eps file in Word, some users with older versions may have difficulty with the file though.





Also, you will get the best result if you scale the image to as close as it needs to be used as even eps files in Word don't seem to retain the crisp lines you would expect them to compared to placing them in software such as QuarkXPress or InDesign.

How to find a vector perpendicular to the plane determined by the following points?

Can you find a vector perpendicular to the plane determined by the following points?





A=(3,1,2) B=(-2,4,0) C=(5, -3, 6)


Also please give me a little explanation.


Thank U very much|||Do you know cross product?





If you know, then the vector that you are looking for is





(B- A) X (C-A)

How can I explain vector art in a simple way to people that don't know what it is?

I have found that it is hard to do and I would like it if someone could tell me a simple way to explain vector art.|||A vector is a picture that can be enlarged and shrunk as many times as needed without losing any quality or detail, and doesn't blur.





A bitmap is a picture (like a jpg) that begins to blur and lose detail if enlarged past its max resolution.





Vectors work great for logos and such that need to be put on different sized things.





A bitmap needs to be created at a size equal or larger to what it needs to be printed at with a high resolution (72 dpi for screen/web, 150 for print, 300 for glossy print)|||Vector images are created with mathematical algorithms where as raster images are created with pixels.





May I suggest wikipedia (http://en.wikipedia.org/wiki/Vector_graphics) for a detailed answer.

What is the unit vector parallel to u, but running in the opposite direction?

(each 'u' should have an arrow above it)





If u=(4,2,-2), what is the unit vector parallel to u but running in the opposite direction? Express your answer in algebraic form.











How do you solve this?|||the magnitude of u is sqrt of( u dot u). The unit vector of u is u / mag of u





so mag. of u = sqrt(4^2 + 2^2 +(-2)^2 ) = sqrt(16 +4 + 4) = sqrt(24) =


2 sqrt(6)


unit vector u = (2/sqrt(6), 1/sqrt(6) , -1/sqrt(6)





the unit vector in the opposite direction is - this vector or


(-2/sqrt(6), -1/sqrt(6), 1/sqrt(6))|||(1/sqrt6)(-2, -1,1)

How is the k vector related to the index of refraction?

I know k is a vector, bu how does it relate to the index of refraction?


This is for plasma physics, specifically whistler waves|||k is called the angular wave number. It is defined such that its magnitude is 2*Pi/lambda, where lambda is wavelength.





Do realize that the formula v=lambda*f must relate frequency to wavelength and wavespeed. Recall index of refraction is defined as n = c/v.





ALSO, most importantly, it is frequency which is unchanged during changing of optically dense media. Wavelength is sacrificial, and thus k is sacrificial as well. Change the value of n, and both lambda and k vary such that v=lambda*f, or v=omega/k can still be satisfied

What is a "Vector field equation" and where can I learn [quickly] how to solve problems with them?

I have a placement exam in university tomorrow that will allow me to skip my entire calculus requirement. The only part of the included syllabus that I have no covered are "vector fields".





What are these, (I know that they have functions..?).


Where can I learn the theory behind them, and where they fit into math, (or how to solve problems involving them with good explanations).|||a vector field is (loosely speaking) a function from R^n to R^n (usually n = 2 or 3).





vector fields are often defined by their coordinate functions, for example, in 3 dimensions, you would write:





F(x,y,z) = (F1(x,y,z),F2(x,y,z),F3(x,y,z))





where each of the F1,F2 and F3 are real-valued functions of 3 variables.





the functions F1,F2, and F3 are in turn, examples of what are sometimes called "scalar fields".





a scalar field is just a function F:R^n --%26gt; R ( a real-valued function of n variables).





since a real-valued function of n variables has n possible partial derivatives, we can form a natural vector field from any scalar field called the gradient:





grad F = (∂F/∂x1, ∂F/∂x2,...,∂F/∂xn)





(the gradient is often indicated with an upside-down delta sign).





the gradient is a generalization of the derivative for functions of more than one variable: at every point of a scalar field, the gradient points in the direction of greatest rate of change of the scalar field, and the magnitude of the gradient is the greatest rate of change.





just as one might ask whether there exists a function whose derivative is f(x), for a given function f:R--%26gt;R (which is what we do when we integrate), one can ask if, given a vector field F:R^n--%26gt;R^n, whether or not that vector field is the gradient of some scalar field.





honestly though, if you haven't been exposed to this material, i'm not entirely sure if it is a good idea for you to skip your calculus courses, unless you never plan to use math again.

What are the copyright laws when making vector images?

What are the copyright laws when making vector images? If I take, for example, an image of someone like David Beckham off the internet and turn it into a vector and then print it on a t-shirt, is that breaking copyright laws?|||Yes, and also probably some trademark infringement issues.





http://www.copyright.gov





/

What's the difference between abstract art and vector art?

I am looking up a few designs and was wondering what the actual difference was, since I've seen very similar pictures listed as both abstract and vector (depending on what site I'm on). Thank you.|||I'm a digital artist.





The words "vector" and "abstract", as applied to images have nothing at all in common.





Abstract is a STYLE of artwork in which an artist might work - just like an artist might do cubism or pointilism.





Vector is a technical method of putting an image into a DIGITAL IMAGE FILE FORMAT. Many artists know nothing about this technical digital image file format stuff. They make pictures, the underlying digital image format particulars may not concern them. Their image editing program or camera takes care of these details.





So, an artist could make a vector-based image which is abstract or one which is figurative, or any other style. Same for a raster-based image.





An "abstract" image is abstract art, as opposed to "representational" or "figurative" art.





A vector image is a digital image made by using a list of X and Y point co-ordinates, angles, lengths and colors to represent an image. That is, opposed to a "bit-mapped" image, which uses a "raster".





The Vector image method tells the computer "Start at this point and then draw pixels of such-and-such a color at this angle for this length and then go to the next item in this list." A raster image tells the computer to start at the upper left and start filling the image boundaries with colored pixels, line-by-line from left to right until the image boundary is filled.





Vector images have areas of solid color, like a map or a cartoon drawing. Bit-mapped images have continuous tones, like a photo. A typical bit-mapped image file format is JPEG or "somepicture.jpg", while a typical vector image file format would be "somepicture.gif".





See the Wikipedia references for more.





Hope this answers your question...


_jim coe|||'Abstract' covers the whole field of non-representational art. I presume that 'Vector' is a type of abstract art, like, say, 'Op Art' and 'Vorticism' are types of abstract art.

How to find vector between 2 points not in reference to the origin ?

Hello, I have 2 points (A and B) in 3D space. I have the coordinate for them A(x1,y1,z1) and B (x2,y2,z2). I want to find the vector that connect them not in reference to the origin but in reference to the point B. Could someone help me with some tips ?


Thanks,


Victoria|||There may not be a non vector unit unless it is : -


V(t) = B + t*%26lt;x1-x2, y1-y2, z1-z2%26gt;|||Parametrically, the vector V can be represented by:



V(t) = B + t*%26lt;x1-x2, y1-y2, z1-z2%26gt;



Note that when t=1,

V(t) = %26lt;x2, y2, z2%26gt; + %26lt;x1-x2, y1-y2, z1-z2%26gt; = %26lt;x1, y1, z1%26gt; = A

How do I find the matrix representation for the orthogonal projection onto vector v?

Say I have a vector [1 3]^t. How do I find the matrix representation for Pv by finding what it does to the standard basis vectors, e1 and e2?|||I'm not sure what you are asking. If you want to project a vector V onto a standard basis composed of E1 and E2, then:





If E1 and E2 are orthonormal, then any vector V = (V.E1)E1 + (V.E2)E2.





Notes:


- E1 and E2 are orthonormal if they are perpendicular and have length 1


http://en.wikipedia.org/wiki/Orthonormal鈥?/a>





- (A.B) means the dot product of the vectors A and B. The results is a scalar that gives the length of component of B parallel to A times the length of A (which is equal to the length of the component of A parallel to B times the length of B)


http://en.wikipedia.org/wiki/Dot_product





If, on the other hand, you have some linear transformation, then you can find its matrix representation by seeing what it does to E1 and E2.





Let the transform be T:


T11 T12


T21 T22





Then since E1 is (by definition) %26lt;1, 0%26gt;, if T(E1) = %26lt;X1, Y1%26gt;, then:


T11 = X1 and T21 = Y1





Similarly, since E2 = %26lt;0, 1%26gt;, if T(E2) = %26lt;X2, Y2%26gt; you get:


T12 = X2 and T22 = Y2

How do you draw a position vector and a projection vector?

For ex. Draw the position vector OP if P(2,3,-4), then draw the projection of OP onto the xy plane.|||for OP draw a line from the origin to the point P



the projection vector of OP onto the z = 0 plane is %26lt; 2 , 3 , 0 %26gt; , again



from the origin to the point ( 2 , 3 , 0 )

How do you find average acceleration in unit vector notation?

Given the equation of a proton v(vector)=4.0i-2.0j+3.0k for 4 seconds, what is the proton's average acceleration in unit-vector notation? Any help here would be great guys. I know how to find the magnitude of the acceleration vector (which should be 1.346 m/s^2) if that helps. Thank you all in advance!|||Acceleration (x-axis) = 4/4 = 1 m/ s^2


Acceleration (y-axis) = -2/4 = -0.5m/ s^2


Acceleration (z-axis) = 3/4 = 0.75 m/ s^2





thus,


a = 1.0i - 0.5j + 0.75k

How to tell if a line integral is a scalar or a vector?

I can't tell if this is a scalar line integral or a vector line integral. It has an orientation, which makes me think its a vector, but the line integral, when evaluated, is just a number, which makes me think scalar. Thank you so much!





The problem:


Line integral 鈭玞 (y^2 dx + 6xy dy), where C is the boundary of the region bounded by y=sqrt(x), y=0 and x=4, and oriented in the clockwise direction.|||Well, you have a dx and a dy, which suggests that it is a vector line integral. Parametrize C as



y = t

x = t^2



and now t goes from 0 to 2.



So the integral is over the curve C(t) = t^2i + tj and C'(t) = 2ti + j.



Let F(x,y) = y^2i + 6xyj. Then F(C(t)) = t^2i + 6t^3 and



F(C(t)) dot C'(t) = 2t^3 + 6t^3 = 8t^3



So we integrate 8t^3 dt from 0 to 2. This ends up being 32.



I'm not really sure how you would have even begun to do this as a scalar line integral...|||Don't quote me on that; I did it pretty quickly.

Report Abuse

How can you tell if a plane or a vector passes through the origin?

By simply looking at a vector how can I delineate if it passes through the origin or not?|||For a plane, it's very easy. Just make sure you have a constant of zero. Example: x-5y+2z=0, and this passes the origin as (0)-5(0)+2(0)=0.





For a vector, it's pretty easy too. You should check if your given point and your direction vector are multiples of each other. If your equation reads something like





r = (1,2,3) + s(2,4,6), s is any real number, it passes the origin as (1,2,3) is a scalar multiple of (2,4,6).

How do I calculate the binormal vector without using the principal unit normal vector?

I can use the tangent vector and a point.|||im not sure try helping me out tho http://answers.yahoo.com/question/index?qid=20110922193638AAsaoWu

How do I know if an image I created in illustrator i vector or raster?

I need a strictly vector picture for a project. How can I ensure that everything in the image is vector? Does using any filters make it raster?|||Some of your filters may be raster effects on a vector image; you do have to be careful with them because you can sometimes get some odd problems when you print (even a pure vector image is actually rasterized for printing: professional digital printers use what is called a RIP: Raster Image Processor). So I would avoid using much in the way of filters, especially any of the Photoshop type filters.





But other than that, anything you do in Illustrator is by default a vector, since Illustrator is a vector drawing program.|||Anything you create in Illustrator is vector unless you convert it to raster or save it in a raster format. Some filters will change it to raster, but they will warn you before hand.|||vector is lines using math, raster is pixels like a photograph. It very easy to tell the difference, if you select all when everything is unlocked anything that is vector will highlight blue usually. if its rasterized then it will only highlight the box around it.

How to find a vector from two endpoints?

So I have the two terminal points of a vector, (1,3) and (-1, 5), and I have to find the vector. Normally, you would just subtract the points, but wouldn't that give you a vector in the first quadrant? So, how are you supposed find this specific vector?





Please explain!


Any and all help welcome!


Thanks so much!|||(-1-1, 5-3) = (-2, 2)


The resulting vector can be in any quadrant.

How do you know when a vector is velocity?

Basically, how do you know when a given vector is velocity and WHY is velocity a vector? Velocity is basically just rate, right? Thats another thing, why are there the two equations: r=d\t and V=S\t arent they just saying the same thing except one deals with distance and one with displacement. Thanx to who can explain this! Please try to make it simple.|||Dude...use the correct slashes for division. "/" means division, and "\" doesn't really have any use in mathematics.








The deal is, velocity is a vector BY DEFINITION. Yes it is a rate, but it is a rate of a vector quantity. Namely position. You need BOTH distance from origin and direction to specify position, hence it is a vector.





Change in position (aka displacement) per unit time yields a vector quantity.


UNLIKE change in distance per unit time, which yields a scalar, which we call speed.


------------------------


"how do you know when a given vector is velocity?"





Check the units. Velocity has units of meters/second.





Other vectors have different units. Such as acceleration has units of meters/second^2. OR displacement has units of meters. Or force has units of Newtons.|||Identifying a velocity vector should be easy. Just see the units, should be m/s. Even if someone gives you a vector, units must be specified, otherwise it makes no sense.


Take two cars. One moving west, other north. Same speed. Are they same? I think not, directions are different right? Just to take this into consideration, velocity was created. Any quantity which changes with change in direction is similar to velocity and this group is given a name, vector.


V=S/t gives average velocity in the direction of displacement only.


r=d/t Distance is scalar as you might know. So r cannot be velocity, has to be average speed, so that LHS=RHS=scalar quantities|||When a rate is vector it is a velocity. A rate is one dimensional velocity. In one dimensional situations the terms are often used interchangeably.





If I am going 50 mph in my car this is a rate. If I am going South at 50 mph in my car, this is a velocity. Velocity has both a magnitude and a direction.|||Velocity,V and Speed,R both have same magnitude but they aren't same things.Velocity has direction + Magnitude ,so it is a vector.Speed has only magnitude,thus it is scalar.Velocity is not just rate,it is rate + direction that's why it is a Vector.I hope it would help you.:-)

What was the upward component of the average acceleration vector of the ball? Physics question?

You throw a ball upward with an initial speed of 4.52 m/s. When it returns to your hand 0.92 s later it has the same speed in the downward direction (assuming air resistance can be ignored). What was the upward component of the average acceleration vector of the ball?|||4.52^2 = 2gh





4.52^2 = 20.4304





20.4304/(2 x 9.8) = h = 1.0424 m





1.0424 = 1/2gt^2





1.0424/4.9 = t^2 = 0.2127, sq-rt = t = 0.46122





0.46122 x 2 = 0.9224 secs ( just checking your time given was correct, it is!)





(v - u)/t = acc (a)





(0-4.52)/0.46 = - 9.826 m/s^2 (answer)|||HyperPhysics.info is an awesome tool for physics homework. A quick search for "constant acceleration" gives:





http://hyperphysics.info/?cx=partner-pub…





Click the top link, that will give you the governing equations. Then click the second link and scroll down to the built in calculator to check your work.

How do you find the scalar, vector and orthogonal projections?

Let a = (-4, -4, -10) and b = (-4, 9, 6) be vectors. Find the scalar, vector, and orthogonal projections of b onto a.|||The scalar projection is just b鈭檃/||a||. The vector projection is the product of this scalar with a unit vector in the direction of a. So the vector projection is





proj_a(b) = (b鈭檃/||a||虏) a





and the orthogonal projection is the difference b - proj_a(b)----this allows you to write b as the sum of two vectors, one parallel to a (the projection onto a) and one perpendicular.





a鈭檅 = 16 - 36 - 60 = -80





||a|| = 2鈭?33).





So the scalar projection is -80/(2鈭?33)) = -40/鈭?33). The vector projection is








proj_a(b) = -80/(2鈭?33))虏 (-4, -4, -10) = (-20/33)(-4, -4, -10)





and





b - proj_a(b) = 1/33 (-212, 217, -2).

Is there really proof that the vector marketing company is a scam?

I've read many sites that make it appear the vector marketing is a scam. None of these sites seem real, they seem like scammed sites. But then again, nothing is saying anything positive about vector marketing. So, who can find me a definite answer and proof?|||It really isn't a "scam" however you have to purchase your sales kit. Provide a long list of names and names and you only get paid commission if you make a sale of an extremely expensive inferior quality knife set.|||It's actually not a scam...Some websites ask have you ever heard of a job that maes you pay for your demonstration packet.... ummm yes Mary Kay $500... and Vector is only $145 which is totally refundable if you chose to quit. mary Kay on the other hand you can't return because they are open and used

Report Abuse

|||I have recently been hired there and have also seen the sites claiming it's a scam. From what I've read if you are a good salesman this is the job for you but if not then look elsewhere. Also, if you take the job don't think you have to sell solely to friends and family.

Report Abuse

|||All the "proof" people have that Vector is a scam are things you're either told at the initial interview (at least I was) or is on their website. They aren't out to scam you but you do have to be a good salesperson. This to me is common sense. Good salespeople are successful at selling things.

Report Abuse

|||smedrik: I just got a job at vector today and you dont have to make a sale to make money they pay you by appointment whether you make a sale or not

Report Abuse

|||I am also a vector employee. You don't have to buy the kit you can borrow ( with a deposit for obvious reasons)You CAN make commision when your total sales reaches certain check points( 10% at 1000, 15% at 2000..ect) or you can make $14 an appnt.It's a great job and not a scam at all

Report Abuse

|||A+ by better business bureau = not a scam. In business since 1981 = not a scam (scams are out of business in a year or so). Taught in college classrooms as a credit sales class = not a scam. Sites that say it is are sites that make money by scamming people into reading pointless crap.

Report Abuse

|||I actually just started working for them and I really doubt its a scam. I guess I'll find out when i get my first pay check.

Report Abuse

|||secretary for the **** hole for 7 months,it is not a scam b/c you can make money but you must pay up front, you will not be paid automatically nor for training. it is a scam to those inner city kids who just want to get a job, not get the run around from a know it all boss who a few years older

Report Abuse

|||It is not actually a scam as they don't steal anything from you - it is called a pyramid scheme. You see they hire every person that comes thru the door. They make you buy one of the products you will be selling as a display model to show to prospective buyers. They will ask you to market/sell to your family and friends. They figure if they hire everyone and each person buys one of their products they make out right there. They also figure every employee they hire will usually make at least 2 sales - maybe to a parent or aunt or uncle - thats 3 sales per employee. If they hire 1,000 people a day, well you get the picture...





They don't pay you unless you sell something so they take no risk in hiring you or anybody else because they at least have the 1 sale from you for the demo model|||its not a scam persay but its not worth getting a job there because you have you have to perchase your sales kits that are knifes, plus you have to go to a three day thraining session that last all day without getting paid for. Also, you are paid per appointment you get and that commission (not a base pay like they claim which they told me). You start with you friends and family first and they are suppose to referre you but if no, they will provide you with a list of current customers (they claim are current customers) to buy up to date products that they may not have or it time for them to get another set. Yes, they hire any one that walks through the door. WHen I seen their ad in the paper, it said one thing. When I called them, they said something slightly different but when I went there, I was a whole new ball game. I was hired on the spot but never went to the trainig because three days unpaid training and it was all day from the morning to afternoon and plus on the third day you have to buy the kit. If not you can't start until the kit is bought. Why pay to get a joband you are trying to get a job to get paid. Plus you have to remember, the economy is bad and no one is going to buy stuff like that because its not a prioity. Also, you may not know many people and if you do, what are they chances they are going to buy it. Also, your friends and family is limited so you cant keep selling to them ( how many knives are they going to sell). Over all, you will make little ot no money and I know this for a fact because a worker came into the office because he hasn't received his check like was was suppose for the pay period and it was for $70 (they pay outs are every two weeks) and he had to wait until next pay out to get it or pay for them to ship it over night on fed ex.|||It's Cutco. You're selling knives. You need to go to unpaid training, buy a set of knives (about $200), and then are asked for a list of 50 names. These are the people that you sell to. Sure, its not a scam in that they're taking money from your bank account, but it's purely a sales organization that you, as a bottom level sales person would have very little chance at actually making a decent amount of money at.|||I would go with what the majority of former employees or clients are saying about a company. The saying, "when in doubt, throw it out" is about spoiled food can include thinking about one's ideas. (Another variation of that saying it 'when in doubt, get it checked out' about health problems :)

How do I draw vector addition on a cartesian coordinate system?

Say if I have 2 vectors, a and b:


a = (3,4)


b = (5,1)





I know that vector a + vector b = (8,5).





But how do I draw it and how can I prove or show that the resultant indeed is (8,5). The thing that confuses me is the location of the vector tails. Should the tails be in the origin for a and b?





Please help!|||Starting at the origin, draw vector a.





Then, starting at the head of a, draw vector b.





Then, draw a vector from the origin to the head of b.





This vector is a+b|||use the head to tail method. place one vectors head at the end of the others tail and draw the resultant. and then use the formula c=sqrt(a^2+b^2) and to find the direction you take tan(B/A)

How to convert photoshop paths made into vector mask layers to vector graphics?

I did a drawing form a photo by tracing the shapes with pen tool, then filled the paths with color and turned them into vector mask layers. Is there any way to make a vector files out of this?|||File %26gt; Export %26gt; Paths to Illustrator

What is the average magnitude of the poynting vector?

I am given the average power a radio transmitter in space transmits isotropically. How do I calculate the average magnitude of the poynting vector at a given distance away from the radio transmitter?|||The average value of the Poynting vector is zero for isotropic radiation.

How is it that position is a vector, when a vector needs a direction?

If a particle has a certain position, it is not moving, and hence cannot have a direction. So how can it have a vector? Does the vector direction refer to the direction it would move if it WE'RE moving?|||In order to understand a position vector, first understand a displacement vector.





Displacement is the math/science term for a distance with a direction. Distance is to displacement as speed is to velocity. The first of each pair are scalars, the second are vectors. The idea of a displacement is it completely tells you how to get from point a to point b. For example, the displacement from (3, 2) to (1, -3) is [-2, -5], or it can also be described as having magnitude 5.4 and direction 248 degrees.





Now a position vector is just a displacement vector that assumes point a is the origin, (0, 0). The componentwise representation of the vector will have the same values as the coordinate pair for the position it represents. The magnitude and direction aren't very interesting, but representing a position as a vector allows you to mix it with other vectors where the magnitude and direction are interesting. For example you can add a displacement vector to a position vector to get another position vector.|||Vectors can refer to a bunch of different physical quantities, such as position, velocity, and acceleration. All vectors are is just a magnitude with a direction. The reason why position vectors exist (and why they're necessarily vectors) is that every point in space, relative to an origin point, has a direction and a magnitude. Even when we use an ordered pair like (1, 2), we're using vectors! It just means 1 unit along the x-axis added to 2 units along the y-axis.


Note that this has nothing to do with the actual velocity of the particle at that given time. The velocity is constant and independent of the particle's instantaneous position if there are no external forces acting on it.|||If a particle has xyz coordinates (4,3,-5) for example, it's position vector is the the displacement which would move it from the origin to the position (4,3,-5).





A 'position-vector' is not a true vector, but is very similar and can be treated mathematically as a vector for most purposes.





It is not a true vector because one end has to be the origin. A true vector isn't tied to particular location; it can be 'moved around' (providing its magnitude and direction are not changed) and still be the same vector. This is not true of a position-vector.|||No apostrophe in were. If an apostrophe is placed there, it reads "WE ARE".??


What you are asking is rather like "at x instant in time, how fast is object Y travelling?", which is 0, because in an INSTANT no movement can possibly occur. But people still expect a speed be given!


You particle has a direction from the origin relative to vectors, usually termed X and Y for 2 planes.Your particle does not have to be moving. It is still in that relative position.|||Position is a location in space-time. It has both magnatude and direction in a coordinate system





5 is not a position





(5,3,2, 11:45 Z) is|||If it's a position it's with respect to some point (like the origin) so give it a distance and you just have a position somewhere on the surface of a sphere, give it direction and you hve a point.

How do I save a transparent Illustrator vector file so it stays as a transparent vector?

How can I save a semi transparent vector file using illustrator so that it stays as a vector %26amp; is still partly transparent with out saving it as a illustrator eps becuase the person I am sending it too doesn't have illustrator...





Thanks|||save it as a pdf instead. You can still edit the pdf in illustrator (trade secret). Alsong as a PDF is created in illustrator then saved you can still open it up and edit it. Just do not flatten the image or rasterize it

Will a vector at 45° to the horizontal be larger or smaller than its horizontal and vertical components?

Will a vector at 45° to the horizontal be larger or smaller than its horizontal and vertical components? And by what factor will it be larger or smaller?|||Larger. Just remember the Pythagorean theorem. When you draw a right triangle, the vector will be the hypotenuse. Since it's a 45 degree angle, the vertical and horizontal components are equal. The vector will be larger than them by a factor of square root of 2.|||Larger. It is the vector sum of it's components so it must be larger.





V = sqrt(x^2 + y^2)





since x = y for a 45* angle





V = sqrt(2)x = sqrt(2)y|||each components of all vectors are calculated by multiplying the length of vectors to sine or cosine of the angle. Sines and cosines are always less than 1 so, components are always smaller. It doesn't matter if they are horizontal or vertical

How are vector spaces, subspaces, and spans useful in applications to physics?

I am a physics and math major currently taking linear algebra. I find vector spaces and subspaces of vector spaces to be quite abstract and cannot see any immediate application to physics like I do with my calculus class. Are there many? I would love to know of some applications of vector spaces to physics. Thanks in advance.|||http://www.physics.sfsu.edu/~bland/cours…

How to conceptualize matrix-vector multiplication in Linear Algebra?

I understand how to multiply a matrix and a vector to get a new vector. But I don't understand what is happening or what it really means to do this. Kind of a vague question but I don't know how else to describe it.|||Basically, any linear transformation can be written in the form of a matrix. So matrix-vector multiplication can be thought of as taking a vector and linearly transforming it to another vector (the solution).





There are three types of elementary matrices, those that rotate, those that stretch, and those that reflect. You can break any matrix down into these elementary matrices such that their product is the original matrix. The elementary matrices then give a step-by-step guide as to how the vector is being transformed so that you get to the final (i.e. solution) vector.





For further info, you can check out the wikipedia article entitled 'Linear map' and scroll down to the subsection 'Matrices'.

What is the direction of the displacement vector?

You are walking 44 m North. You then turn 60 degrees to the right and continue to walk for another 45 m. What direction is the displacement vector?|||Let X axis due East and Y axis due North.


Then the components of the displacement vector V are:


Vx = 45*sin60° = 38.97 m


Vy = 44 + 45*cos60° = 66.5 m


and


tanα = Vx/Vy = 0.586


α = 30° North to East.|||start off by drawing a diagram, show a line going north on a piece of paper and label it 44m, then draw another line 60 degrees to the right of north going 45m, then use vector addition and law of cosines and sines to find the magnitude and then find the direction

How to mirror vector A relative to a plane perpendicular to vector X?

For example in R3, vector A(a1,a2,a3) is mirrored to a plane perpendicular to vector X(x1,x2,x3). What is the vector resulted from this mirroring process ?|||Let's assume that ||X|| = 1 (if not, divide X by its norm; it doesn't alter the plane or A), then the component of A in the direction of X is:





A(X) = (A,X)X





Where (...,...) is the inner product. Notice that A(X), being collinear with X, is also orthogonal to the plane, and its mirror image is 鈭扐(X). Now, the mirror image of A in X is given by adding to A twice the mirror image of A(X):





M(A,X) = A 鈭?2A(X)





Where M(A,X) is the mirror image of A. This will be a lot clearer if you draw a picture.

How to solve the magnitude of a vector when it is unknown?

can someone help me to solve or find the magnitude of a vector when it is unknown?





Problem:


Vector A has magnitude of 188 units pointing 30.0 degrees North of West.Vector B points 50.0 degrees East of North, and Vector C points 20.0 degrees West of South. These three vectors add to give a resultant vector that is zero. Find the magnitudes of Vector B %26amp; C.|||The easiest way to solve this is through a graphical solution. But to do this you're gonna need a good ruler and some sort of angle measurer. First draw vector A, in a certain scale, let's say 1 in = 10 units. That means you'll be drawing a straight vertical line which has a length of 18.8 in.





Next you draw vector B from the edge of vector A 50 deg east to north.


Draw a very very long line.





Next you draw vector C from the other edge of vector A, 20 deg west to south. Again draw a very very long line.





You'll then get a intersection where the line representing vector B %26amp; C meet. Measure the line, from that intersection to the edge of vector A. Multiply the measurement with the scale you've already stated in the first step (1 in = 10 units).





Et voila!! You got the magnitude of each vector

What is the magnitude of the resulting vector and the angle?

Having trouble with this problem. Beginner physics but no example in textbook. Vertical component of force is 130 newtons, horizontal is 150 newtons. Do I use Pythagorean or cos to get the angle then sin to get the resulting vector newtons?|||yes, use the Pythagorean theorem to find the resultant





magnitude = sqrt[horizontal component^2+vertical component^2]


mag =sqrt[150^2+130^2]=198.5N





the angle the resultant makes with the positive x axis is given by





tan(theta)=vertical component/horizontal component = 130/150=0.87





tan(theta)=0.87 =%26gt; theta =arc tan 0.87 = 40.9deg

What is the difference between Scalar and Vector quantities?

Scalar only has magnitude while vector has both magnitude and direction. What does that mean?|||It means the difference between speed and velocity. You can say a car is traveling at a speed of 60 miles per hour. That is a scalar quantity and has only magnitude. You can also say the car has the velocity 60 miles per hour due north. That is a vector quantity. It has magnitude, 60 miles per hour, and a direction, due north.





If you have two cars, both traveling 60 miles per hour, they have the same scalar quantity of speed. But, if one is traveling due north, and the other is traveling due south, they have very different vector quantities since they are traveling in opposite directions. Their speeds, a scalar quantity, may be the same, but their velocities, a vector quantity, are very different.





..|||Use this "image" in your mind.





On a Cartesian space (an x-y plot), a vector quantity would be represented by two values (one for the x and one for the y).





In vector notation, the vector would be represented by (for example), the value V = [3 4]





This is the vector that goes from the origin (0, 0) to the point (x, y) = (3, 4).





You could represent it by giving its length (5) and its direction (53.13 degrees or 0.9273 radians). In fact, there exists a system like that called "polar notation", but that will be later in the course.





If you wanted to make this vector [3 4] twice as long (but keep the same direction) you could simply multiply it by 2:





2V = 2[3 4] = [6 8]





In this example, the [3 4] is a vector quantity while the 2 is a scalar quantity. The 2 simply multiplies the magnitude of whatever you want it to multiply: it carries no direction information on its own.





The vector quantity [3 4] carries a direction information (53.13 deg.).


Note that the direction of [6 8] is also 53.13 degrees. That is because multiplication by a scalar does not affect direction.





Multiplication by another vector would affect direction (you will see that later).|||A magnitude is a simple value like 10. A simple value doesn't give you any direction. A vector can give you both magnitude and direction, for example 40x+30y is an example of a vector. This vector might describe where you would end up if you went 30 miles east and 40 miles north.|||scalar has simply an amount, while a vector quantity has both an amount and a direction in which the action is occurring.

How to transfer a vector image from Illustrator Adobe to Publisher?

I have a vector image in Illustrator i need to transfer to Publisher, and need to keep it as a vector image? make the image remain high pixels when i make it smaller ot larger in publisher,How can i do this? Thanks so much!!|||I don't use Publisher (suggestion: switch to Adobe InDesign, it's much more of a standard and works well with Illustrator and Photoshop), so I am only guessing: there are two approaches. One is you can rasterize the Illustrator file: convert to a high res .jpg. Two, does Publisher accept .eps files? If so, then save your Illustrator file as a .eps file and you should be good to go.|||Converting your image to vector file and the vector file can be resized or enlarged as you like.


Vector file is high resolution and if you need someone to convert it to vector file,you can send


to PGCONVERSION.COM. And they alsway help me convert to vector file. Here enclosed their


link:





http://www.pgconversion.com/





http://www.pgconversion.com/index.htm

How do you use vector files in Photoshop CS?

I have some ai vector files that I would like to use, but when I open them in photoshop, they simply appear raster-like and cannot be resized without jeopardizing the quality (they become pixelated). Does photoshop even support the usage of vector images? If so, how do use them?|||To add to answers given above, starting with the CS2 package Adobe synced Photoshop and Illustrator nicely. If you have both, you can import vector layers into Photoshop as "vector smart objects." By double clicking on them in the layer palette it will open them in Illustrator, and any saved changes will take their effect in Photoshop when you return to the program. Not quite the same, but in two totally different graphic worlds (vector and bitmap) its the closest you're going to get to joining them for now.|||Photoshop can import vector-based files, but it is not a vector program, it is a raster program. You'll want Adobe Illustrator. Photoshop will (should) allow you to choose size on import, and will retain the quality of the image if its a true vector image, but other than that it's going to end up in a raster format.|||You can open an ai file in Photoshop however it will always open as a raster,unless you opened it as a Smart Object, by double clicking on it, it will open in Illustrator where you can amend it. I find the best method is to cut and paste from Illustrator into a Photoshop (which you have already sized) as a Smart Object or as a path and use the path to recreate blocks of colour.

How do you find vector equations of a line with two points?

Is it just like vector addition, using position vectors to find the line between the two points?|||If you have learned about directional derivatives, take the direction of the tangent * the directional derivitve of that point to find the vetcor.|||ax + by = c =%26gt; y = -ax/b + c/d





M1(x1; y1 = -ax1/b + c/d ) ; M2(x2; y2 = -ax2/b + c/d)





vector M1M2 = (x2-x1, y2-y1)

How do i convert text to vector shape using fireworks cs4?

Im working on editing a picture for class and i had to add some text. The step i have to do is convert the text to a vector shape, and resize it to about 96 pixels square. I have no idea what that means or how to do it please help! Thanks in advance.|||I don't recall if you can convert text into a vector shape in Fireworks. In general, Fireworks is a PNG maker and the best you might get out of it is text that you can place with a clear background.





The only way I know how to correctly change text to vector is in Adobe Illustrator.





Illustrator instructions;


1. Type out text you want converted.


2. Right click text and select "Create Outlines"


3. Your vector text is NOW ready to use.





I may be wrong in saying that FW can't convert text to vector, but I can't find any resources on that anywhere. Illustrator is the easiest way to do it if you have it. Good Luck.

How would I use a diagram to prove the following properties of vector addition?

How would I use a diagram to prove the commutative and associative properties of vector addition?


A) Vector addition is commutative: a + b = b + a


B) Vector addition is associative: a + (b + c) = (a + b) + c





How would I draw each diagram to prove this? A detailed explanation of a suitable diagram would be awesome!|||Easy. Start at the origin of the cartesian plane, and draw Vector A (which can be any vector you can imagine. Then, start at the end of Vector A and draw Vector B (which can also be any vector in any direction.)





Then, re-draw starting with Vector B at the origin, and Vector A beginning at the end of Vector A.





Another way to work on this is to show that Vector A and B's lengths can be broken up as (L cos 螛, L sin 螛) where L is the length of the vector and 螛 = the angle from the X-axis.|||A) Draw a parallelogram OACB with one corner at the origin O, and vectors OA = a, OB = b.





Since OACB is a parallelogram, OA = BC = a and OB = AC = b as vectors. So





a + b


= OA + AC


= OC


= OB + BC


= b + a.





B) Draw a quadrilateral OABC, with OA = a, AB = b, BC = c. Then





a + (b + c)


= OA + (AB + BC)


= OA + AC


= OC


= OB + BC


= (OA + AB) + BC


= (a +b) + c.

What does the gradient of a vector field give us?

I know that a vector field is a space in which every point is associated with a vector. But what would I be meaning if I talk about gradient of that vector field? What does this gradient actually signify?|||the gradient is a vector; you find the gradient by taking directional derivatives of a scalar field; the gradient tells you the rate of change of the quantity of interest





for instance, suppose you measure the temperature of a room with hundreds of thermometers and can plot the gradient of the temperature field...where the gradient is largest is where the temperature is changing most rapidly, where the gradient is near zero is where the temperature is constant|||Or, another example, check out the weather maps on TV. They show lines across the surface. These lines are called isobars, lines where atmospheric pressure is the same.





When the isobars are closer together, the gradient is steeper than when the isobars are farther apart. The gradient is steeper where the lines are closer because the pressure change per distance dP/dS is greater. In practice the dP = constant on weather maps; so the shrinking distance between them ds %26lt; dS makes the gradient steeper.





In this example, the field is a pressure field, the atmospheric pressure. And at each point along the surface of the Earth, there is a tiny little pressure vector pushing onto the surface. [See source.]|||the slope of the vector field at that point?

What is the best bitmap to vector converter?

I want to convert my photos to vector graphics but I want to know the best software available out there. What can you recommend?|||Adobe c3,cs4 or cs 5

What are the main differences between raster and vector artwork? How do you decide whether raster or vector is?

What are the main differences between raster and vector artwork? How do you decide whether raster or vector is appropriate for a project? Describe one advantage and disadvantage of using raster vs. vector artwork.


I can not figure out what these are.|||Raster artwork is one size: it is also called a bitmap and if you print it at any resolution or size other than the one it was created at it looks terrible. It does have its place in commercial printing, but commercial printing technologies are not ALL that different than what we get on the screen. Bitmap editing or creating and fixing raster artwork is easier than creating vector artwork. Believe me.





Vector artwork is a record of the steps needed to create the artwork. Length or relative length and angle of the lines for example. As such it is usually larger than Raster artwork (which itself can be very big) but the advantage of Vector artwork is you can print the same file onto a business card or a T-shirt or a Billboard poster. In other words it is scalable.





If you know or can figure out exactly how large your image has to be to be effective in advance, go with raster. If you are not sure, or need it at different sizes, go with vector art.|||artweaver free think its raster vector like 3d software but it cost alot artweaver free I like 5.7 more stuff you can do 10. cool get them at cnet or search google hope this helps the picture by name was draw with 10 use layering good luck bub101

(linear algebra) How do I find out that a vector space is the same as another vector space?

I have a vector space consisting of 2 vectors in R^3 and a different vector space consisting of another 2 vectors in R^3. How do I find out whether if they are the same?|||v1, v2 and w1, w2





if v1 x v2 = a (w1 x w2)





where 'a' is a scalar and the 'x' represents the cross product then it is the same space.

Can two vectors of unequal magnitude add up to give the zero vector?

Can two vectors of unequal magnitude add up to give the zero vector?


Can three unequal vectors? Under what conditions?|||Suppose two unequal vectors, A and B, did add up to zero.


A + B = 0


-%26gt; A = -B


-%26gt; magnitude A = magnitude B


-%26gt;%26lt;- contradiction


Apparently the answer is no, they cannot.





It's easy to provide plenty of examples of three different vectors adding up to zero. When you draw them all head-to-tail, they make a triangle.

How do you find a unit vector b perpendicular to another unit normal vector?

How do you find a unit vector b perpendicular to another unit normal vector, which is (4/5)i + (2/5)j - (3/5) k





your help would be much appreciated!





Thank you!|||A vector (4/5)i + (2/5)j - (3/5) k (say)





Then we should remember that the this vector is perpendicular to a plane ...


Then a vector perpendicular to this plane becomes impossible to find as they are infinite.





We cannot find a vector perpendicular to this one in particular..|||when the dot product of the two vectors equals zero, then they are perpendicular to each other

What is the difference between a vector and scalar in physics?

Hello!





What is the difference between a vector and scalar in physics?


Can you also please include an example of both?





Thanks!|||Vector has direction (eg velocity, momentum), scalar is just a number (eg speed). So if you are adding two velocities, you need to consider their directions - if they are not lined up, then your answer will be both lower than a sum of the "speeds", and in a different direction.

What is meant by " vector values of both the electric field and the magnetic field" Diagram ?

What are vector values (this has to do with wave lengths of light)


And what is the magnetic field and electric field? (This has to do with wave lengths, and electrons.)





Can anyone find a diagram of this somewhere?|||See thie http://en.wikipedia.org/wiki/File:Light-…

How do I prove that the zero vector in V is also the zero vector in W?

Let W be a subspace of the vector space V. Prove that the zero vector in V is also the zero vector in W.





I need a proof for this desperately. I got a mid-term tomorrow.|||Since W is contained in V then g+0=g in V for any g in W and 0 the zero vector in V. So 0 in V behaves like the zero vector in W. 0 is also contained in W since g-g = 0 as a relation in V, must also hold true in W. If h is another vector in W with the same properties as 0, then h+0=0, and from above h+0=h, so 0=h.

What does the line integral of a conservative vector field really mean?

I understand that a line integral of a vector function is the area under the curve, but I'm confused about taking the line integral of a conservative vector field because it's independent of the curve. So what does the "answer" really "mean"?|||A physical interpretation is work. You compute the work done moving a particle from one end of the path to the other subject to the force given by the vector field. For a conservative field, the work is independent of the path chosen. But the interpretation of work is equally valid for conservative and non-conservative force fields (in the non-conservative case, you have to integrate along the prescribed path--different paths can lead to different work done.)

How do i draw a vector diagram and find magnitude for this question?

A car is driven 215km east and then 85 km northeast. How do i draw a vector diagram and find its magnitude of the resultant displacement?|||Decide on some accceptable scale: perhaps 1cm = 10km


On your cartesian plane take the +X axis as being due east. On the X axis draw a line 21.5cm long.This will represent the 215km east travel


At the end of this line, at the 21.5cm mark, make an angle of 45° which is in the nort east direction. Draw a second line 8.5cm long. This will represent the 85km nort east travel.


Now join the origin to this end mark on the NE line. This line is the displacement of the car from the start in magnitude and direction. Measure this line in cm, multiply by 10 to give you the magnitude of the displacement, and with a protractor, measure the angle between the line and the X-axis, which is the direction of the resultant displacement.|||plot head to tail usin' the xy plane,


then, just use the cosine law to calculate the magnitude.|||First draw a normal x/y plane. Draw a vector of magnitude 215km (vector "a") directed to the right along the x axis. Starting from the tip of that vector, draw another vector of magnitude 85km (vector "b") directed 45 degrees above horizontal.





Splitting vector "b" into components b(x)= bcos(45) and b(y) =bsin(45)


We can now see a right triangle. Base = a + bcos(45) Height = bsin(45)


we will call the resultant displacement vector "x"


using the pythagorean theorem:


x= Square Root [ (a +bcos(45) )^2 + (bsin(45) )^2 ) ]


finding that x = 281.593 km





we can find the angle of this resultant vector by saying:


tan(Theta) = bsin45 / (a+bcos45)


take the arctan of both sides... we find that


Theta = 12.32 degrees





Hope that helps.

What is the average magnitude of the Poynting vector?

A radio transmitter in space transmits isotropically with an average power of 170 kW. What is the average magnitude of the poynting vector 14 miles from the radio transmitter?





Answer in units of W/m^2.





I read the section on Poynting vectors twice but I haven't begun to figure out how to solve this.. Please help!|||S= P/ ( 4*pi*distance^2)


Power = 170x10^3


Distance = 14 miles * 1609 = 22526m





S = 170x10^3 / (4 * pi * 22526^2 ) is the answer in W/m^2

How do you make a vector addition program for your graphing calculator?

I need to make an vector addition program for my physics class. I need the code to make it.|||1. Go here and find the one you need: http://www.ticalc.org/pub/83plus/basic/m鈥?/a>





2. Download it, extract it.





3. Go to http://sc.cemetech.net and upload the file to view the source code.





4. Copy into your calculator.

How can I change the stroke of multiple vector shapes at once in Photoshop?

When I resize my vector art to make it smaller, the problem is that the stroke size stays the same on all my shapes, making it look really bad. I could resize the stroke on each shape, one by one, but is there a way to change the stroke, or any vector effect for that matter, on multiple shapes simultaneously?|||There is in Illustrator. You can use the magic wand in there and it selects all objects with the specific attributes you clicked on.





In PS, I'm not sure. I don't care for the vector capabilities in PS.





If you have Illustrator, you can export the paths to it from PS and edit them from there.





Just a thought|||im not sher but my friend knows all about it email messywedgiegirl@yahoo.com

How do I decide whether a vector is in the column space of a matrix?

Say I have some m x n matrix where each column is a vector and am given some random vectors. How do I decide which of those random vectors would be in the column space of this matrix? I understand that the column space of the matrix will be the span of the vectors in that matrix, but other than that I am lost. It would be nice if someone could tell me how you would do it with row space, too.|||Let's say you have a matrix "A" that's m x n. The "n" column vectors make up a vector space. Now let's multiply this matrix by some n x 1 vector x = %26lt;x1, x2, ..xn%26gt;. The resulting vector ("b") is a linear combination of the column vectors, specifically


b = Ax = x1*col1 + x2*col2 + ... + xn*coln





Now, if we have another vector, "z", and we want to know if it is in the column space of "A", we have to solve the system


z = Ax





for the vector "x"; if there is a solution, then we can write "z" as a linear combination of the columns of "A", and your random vector "z" is in the column space of "A".|||I saw Vector on the street waiting for a car-lift.

What is the difference between a unit vector and a vector component?

Please clearly explain it because I've googled this question, searched forums, and watched youtube videos and I can't get an explanation I can understand. I have a homework problem asking if (i + j + k) is a unit vector, and the back of the book says it is not. Why not? What is it? what would make it a unit vecor?|||i+j+k has both a magnitude and direction. It _is_ a vector.





A Unit vector is a vector of magnitude 1. i+j+k doesn't have magnitude 1.





This might help you in vector addition: i+j+k is the sum of i, j and k


http://www.ucl.ac.uk/Mathematics/geomath…





We need to divide the vector by its magnitude to make it a unit vector, since it will have magnitude one then. So, the unit vector in the direction of i+j+k is: (i+j+k)/sqrt(3)|||I'm not entirely sure,


But a vector must have both magnitude (a value) and direction. i + j + k will give a value but no direction, therefore it can't be a vector.





This is irrelevant, but the components of a vector are simply the x difference value and the y difference value. This is found by using pythagoras and the tangent ratio and is used to add two vectors together.

How to check if a vector is in the span of two vectors?

I need to check if (my book writes these as column vectors)





(2, 6, 6) is in the span of (-1, 2, 3) and (3, 4, 2).





So I know what it's asking. It's asking if some linear combination of the last two vectors produces the 1st vector.|||Check the determinant of matrix


2 -1 3


6 2 4


6 3 2


If it is =0 it means that (2,6,6) is a linear combination of the last two vectors.


If not all three vectors are independent.|||Let r, s be some real numbers. For [2, 6, 6] to be a linear combination of the other two vectors: there must be some scalar multiple of the other two that gives us the [2, 6, 6] vector.





[2, 6, 6] = r [-1, 2, 3] + s [3, 4, 2]


Then:





2 = -r + 3s


6 = 2r + 4s


6 = 3r + 2s





Now to solve for r and s. If we can find some values for them that works, then it is in the span of the two vectors.





Add 2 of the first equation to the 2nd equation:


6 + 4 = (2r + 4s) + (-2s + 6s)


10 = 10s


s = 1





Plug s = 1 into one of the original equations.





6 = 3r + 2s


6 = 3r + 2(1)


6 - 2 = 3r


4 = 3r


r = 4/3





Plug these values into the first equation:


2 = -r + 3s


2 = (-4/3) + 3


-1 = -4/3





That is obviously not true. Thus, not in the span.

How to take vector group test of a transformer?

Suppose we dont know the vector group of transformer, how to check its vector group through test? I have 3 transformer DYn11 %26amp; DYno%26amp; Ynd11, how to confirm its vector group?|||Dissolved Gas Analysis (DGA) is a proven and


meaningful method. If increased levels of


hydrocarbon gases are found in the oil, the fault


must be located as soon as possible. Hence


important preventative maintenance must be


performed in time to avoid an unexpected


total failure.


The most frequent


sources of faults are the tap changers, bushings,


the paper-oil insulation and the accessory


equipment.


In order to find the source and reason for


high gas values, further tests have to be


performed on the transformer. Common test


methods are:


l Turns ratio, vector group and excitation


current measurement


l Static winding resistance measurement


l Dynamic winding resistance measurement


to test the on-load tap changer (OLTC)


l Sweep frequency response analysis


(SFRA) measurement


l Frequency dependant capacitance and


dissipation factor measurement


l Di-electric response analysis


l Partial discharge (PD) measurement


Turns ratio, vector group and excitation


current measurement


The transformer turns ratio test (TTR) is performed


by applying a test voltage (typically 500 V


L-L) to the HV winding of a transformer and


measuring the LV voltage. The test can either


be performed as single-phase or threephase


and typically is performed for each


tap step of a tap-changer. In the case of


a three-phase injection and if testing a YD


or DY transformer, the injected or measured


voltage on the delta winding needs to be


adjusted by a factor of 鈭?.


The vector group test (VG) is performed in a


very similar fashion as the TTR test 鈥?except


that it is performed by injecting a balanced


three phase voltage, i.e. this test is not


possible with a single phase injection.


http://www.eepublishers.co.za/images/upl鈥?/a>